Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Cumulative Review: 20

Answer

a. $\frac{7}{12}$ b. $-6$ c. $\frac{1}{x^3}$

Work Step by Step

a. $2^{-2}+3^{-1}$ $=\frac{1}{4}+\frac{1}{3}$ $=\frac{1}{4} \times \frac{3}{3} + \frac{1}{3} \times \frac{4}{4}$ $=\frac{3}{12} + \frac{4}{12}$ $=\frac{7}{12}$ b. $-6a^0=-6(1)=-6$ c. $\frac{x^{-5}}{x^{-2}}$ $=x^{-5-(-2)}$ $=x^{-3}$ $=\frac{1}{x^3}$
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