Answer
Please see the graph.
Work Step by Step
Red line: $f(x)=x^2$
Blue line: $g(x) = x^2-1$
We pick three values for $x$ to determine the applicable $y$ values for both graphs.
$x=-2$
Red line:
$f(x)=x^2$
$f(-2)=(-2)^2$
$f(-2)=4$
$x=0$
Red line:
$f(x)=x^2$
$f(0)=0^2$
$f(0)=0$
$x=3$
Red line:
$f(x)=x^2$
$f(3)=3^2$
$f(3)=9$
$(-2,4)$, $(0,0)$, and $(3,9)$ are on the red graph.
$x=-2$
Blue line:
$g(x) = x^2-1$
$g(-2) = (-2)^2-1$
$g(-2)=4-1$
$g(-2)=3$
$x=0$
Blue line:
$g(x) = x^2-1$
$g(0)= 0^2-1$
$g(0)=0-1$
$g(0)=-1$
$x=3$
Blue line:
$g(x) = x^2-1$
$g(3) = 3^2-1$
$g(3)=9-1$
$g(3)=8$
$(-2, 3)$,$(0, -1)$, and $(3,8)$ are on the blue graph.
