Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.3 - Polynomial and Rational Functions - Exercise Set - Page 594: 22

Answer

a) 0 seconds: 960 feet; 3 seconds: 1008 feet; 6 seconds: 768 feet; 9 seconds: 240 feet b) Eventually, $abs(-16t^2) > abs(64t+960)$, so the object will hit the ground. c) $-16(t-10)(t+6)$

Work Step by Step

$h(t)=-16t^2+64t+960$ a) $t=0$ $h(t)=-16t^2+64t+960$ $h(0)=-16*0^2+64*0+960$ $h(0)=-16*0+64*0+960$ $h(0)=960$ $t=3$ $h(t)=-16t^2+64t+960$ $h(3)=-16*3^2+64*3+960$ $h(3)=-16*9+192+960$ $h(3)=-144+1152$ $h(3)= 1008$ $t=6$ $h(t)=-16t^2+64t+960$ $h(6)=-16*6^2+64*6+960$ $h(6)=-16*36+384+960$ $h(6)=-576+1344$ $h(6)=768$ $t=9$ $h(t)=-16t^2+64t+960$ $h(9)=-16*9^2+64*9+960$ $h(9)=-16*81+576+960$ $h(9)=-1296+1536$ $h(9)=240$ c) $h(t)=-16t^2+64t+960$ $-16t^2+64t+960$ $-16(t^2-4t-60)$ $-16(t-10)(t+6)$
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