Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.3 - Polynomial and Rational Functions - Exercise Set - Page 594: 16

Answer

a) 910 feet b) 911 feet c) 797 feet d) 560 feet e) Eventually, $abs(-16t^2+10t) > 910$. Because of this, the football will eventually hit the ground. f) 8 seconds

Work Step by Step

$P(t)=-16t^2+10t+910$ a) $t=0$ $P(t)=-16t^2+10t+910$ $P(0)=-16*0^2+10*0+910$ $P(0)=-16*0+0+910$ $P(0)=0+910$ $P(0)=910$ b) $t=1/2$ $P(t)=-16t^2+10t+910$ $P(1/2)=-16(1/2)^2+10(1/2)+910$ $P(.5)=-16*1/4+5+910$ $P(.5)=-4+5+910$ $P(.5)=1+910$ $P(.5)=911$ c) $t=3$ $P(t)=-16t^2+10t+910$ $P(3)=-16*3^2+10*3+910$ $P(3)=-16*9+30+910$ $P(3)=-144+940$ $P(3)=797$ d) $t=5$ $P(t)=-16t^2+10t+910$ $P(5)=-16*5^2+10*5+910$ $P(5)=-16*25+50+910$ $P(5)=-400+960$ $P(5)=560$ f) $P(t)=-16t^2+10t+910$ $t=7$ $P(t)=-16t^2+10t+910$ $P(7)=-16*7^2+10*7+910$ $P(7)=-16*49+70+910$ $P(7)=-784+70+910$ $P(7)=-714+910$ $P(7)=196$ $t=8$ $P(t)=-16t^2+10t+910$ $P(8)=-16*8^2+10*8+910$ $P(8)=-16*64+80+910$ $P(8)=990-1024$ $P(8)=-34$
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