Answer
$f$($x$) = $3x^{2}$ - $x$ + 2 when $f$(-1)
$f$(-1)= 6
Work Step by Step
$f$($x$) = $3x^{2}$ - $x$ + 2 when $f$(-1)
First replace $x$ with -1
$f$(-1) = $(3 \times-1)^{2}$ - (-1) + 2
Next multiply 3 and -1 (which makes 3 negative) and add 1 and 2 (When a negative is subtracted it becomes positive)
$f$(-1) = $-3^{2}$ - 3
$f$(-1) = 9 - 3
$f$(-1) = 6
