## Algebra: A Combined Approach (4th Edition)

$f$($x$) = $3x^{2}$ - $x$ + 2; when $f$(2) $f$(2) = 12
$f$($x$) = $3x^{2}$ - $x$ + 2; when $f$(2) First replace $x$ with 2 $f$(2) = $(3 \times2)^{2}$ - 2 + 2 Next multiply the terms in (*), and drop (-2 + 2) because it equals 0 $f$(2) = $6^{2}$ Finally multiply $6\times6$ $f$(2) = 12