Answer
$f$($x$) = $3x^{2}$ - $x$ + 2; when $f$(2)
$f$(2) = 12
Work Step by Step
$f$($x$) = $3x^{2}$ - $x$ + 2; when $f$(2)
First replace $x$ with 2
$f$(2) = $(3 \times2)^{2}$ - 2 + 2
Next multiply the terms in (*), and drop (-2 + 2) because it equals 0
$f$(2) = $6^{2}$
Finally multiply $6\times6$
$f$(2) = 12