Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Cumulative Review: 41

Answer

y=$\frac{5}{3}$x+$\frac{13}{3}$

Work Step by Step

3x+5y=4 5y=4-3x 5y=-3x+4 y=-$\frac{3}{5}$x+$\frac{4}{5}$ slpoe is -$\frac{3}{5}$ The line perpendicular has the slope $\frac{5}{3}$,through (-2,1) y=mx+b 1=$\frac{5}{3}$(-2)+b 1=-$\frac{10}{3}$+b $\frac{3}{3}$+$\frac{10}{3}$=b $\frac{13}{3}$=b y=mx+b y=$\frac{5}{3}$x+$\frac{13}{3}$
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