## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 7 - Test - Page 562: 30

#### Answer

Out of 510 florescent bulbs, 18 would be defective.

#### Work Step by Step

Given: Out of 85 florescent bulbs, 3 were found defective. Thus, if there were 510 florescent bulbs, then $\frac{510 \times 3}{85}$ would be defective..... (Cross multiplying $\frac{3}{85}$ = $\frac{x}{510}$ , where x is number of damaged bulbs.) $\frac{510 \times 3}{85}$ = $\frac{85 \times 6 \times 3}{85}$ = 6 $\times$ 3 = 18. Thus out of 510 florescent bulbs, 18 would be defective.

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