Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Test - Page 562: 21

Answer

There is no solution for this equation.

Work Step by Step

$\frac{10}{x^2 - 25}$ = $\frac{3}{x + 5} + \frac{1}{x - 5}$ $\frac{10}{(x + 5)(x - 5)}$ = $\frac{3(x - 5) + (x + 5)}{(x +5)(x - 5)}$ $\frac{10}{(x + 5)(x - 5)}$ = $\frac{4x - 10}{(x +5)(x - 5)}$ Hence, $10 = 4x - 10$ $4x = 20$ $x = 5$ But, when $x = 5$, the equation will be undefined since $x$ cannot be equal to 5 or -5, therefore, there is no solution for this equation.
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