Chapter 7 - Section 7.6 - Proportions and Problem Solving with Rational Equations - Exercise Set - Page 536: 8

The solution is $\frac{103}{6}$

$\frac{6}{11}$=$\frac{27}{3x-2}$ 6(3x-2)=11*27 18x-12=297 18x=309 x=$\frac{309}{18}$ x=$\frac{103}{6}$ Check the solution $\frac{6}{11}$=$\frac{27}{3x-2}$ $\frac{6}{11}$=$\frac{27}{3*\frac{103}{6}-2}$ 6(3*$\frac{103}{6}$-2)=11*27 3*103-6*2=297 297=297