## Algebra: A Combined Approach (4th Edition)

equation $x=-7/3$
$\frac{9}{x^2-4}+\frac{2}{x+2}=\frac{-1}{x-2}$ $\frac{9}{(x+2)(x-2)}+\frac{2}{x+2}=\frac{-1}{x-2}$ $(x-2)(x+2)*\frac{9}{(x+2)(x-2)}+(x-2)(x+2)*\frac{2}{x+2}=(x-2)(x+2)*\frac{-1}{x-2}$ $9+2(x-2)=-1*(x+2)$ $9+2x-4=-x-2$ $5+2x=-x-2$ $3x+7=0$ $3x=-7$ $3x/3=-7/3$ $x=-7/3$