Answer
$\frac{29x-23}{3x}$
Work Step by Step
$\frac{10x-9}{x}$-$\frac{x-4}{3x}$=
$\frac{3(10x-9)}{3x}$-$\frac{x-4}{3x}$=
$\frac{30x-27-x+4}{3x}$=$\frac{29x-23}{3x}$
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