#### Answer

$\frac{4(x+2)}{7x(3x-1)}$

#### Work Step by Step

$\frac{4x+8}{7x^2-14x}\times \frac{3x^2-5x-2}{9x^2-1}$
$=\frac{4(x+2)}{7x(x-2)}\times \frac{(3x+1)(x-2)}{(3x+1)(3x-1)}$
$=\frac{4(x+2)}{7x}\times \frac{1}{(3x-1)}$
$=\frac{4(x+2)}{7x(3x-1)}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{4(x+2)}{7x(3x-1)}$

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