#### Answer

$\frac{3}{2}$

#### Work Step by Step

$\frac{3x+6}{14}\times \frac{7x^2}{x^3+2x^2}$
$=\frac{3x+6}{14}\times \frac{7(x^2)}{(x^2)x+2x^2}$
$=\frac{3x+6}{(14)}\times \frac{(7)}{x+2}$
$=\frac{3x+6}{2}\times \frac{1}{x+2}$
$=\frac{3(x+2)}{2}\times \frac{1}{(x+2)}$
$=\frac{3}{2}$