#### Answer

Answer is correct.
$\frac{x+7}{-5x-1}$

#### Work Step by Step

Answer is correct because:
$\frac{7-34x-5x^{2}}{25x^{2}-1}$=
$\frac{7+x-35x-5x^{2}}{25x^{2}-1}$=
$\frac{7+x-35x-5x^{2}}{25x^{2}-1}$=
$\frac{1(7+x)-5x(7+x)}{(5x)^{2}-1^{2}}$=
$\frac{1(7+x)-5x(7+x)}{(5x)^{2}-1^{2}}$=
$\frac{(1-5x)(7+x)}{(5x+1)(5x-1)}$=
$\frac{(1-5x)(7+x)}{(5x+1)(-1)(1-5x)}$=
$\frac{(7+x)}{(5x+1)(-1)}$=
$\frac{(x+7)}{-5x-1}$