Answer
Answer is correct.
$\frac{x+2}{-8x-1}$
Work Step by Step
Answer is correct.
$\frac{2-15x-8x^{2}}{64x^{2}-1}$=
$\frac{2+x-16x-8x^{2}}{64x^{2}-1}$=
$\frac{1(2+x)-8x(2+x)}{(8x)^{2}-1^{2}}$=
$\frac{(1-8x)(2+x)}{(8x)^{2}-1^{2}}$=
$\frac{(1-8x)(2+x)}{(8x+1)(8x-1)}$=
$\frac{(1-8x)(2+x)}{(8x+1)(-1)(1-8x)}$=
$\frac{(2+x)}{(8x+1)(-1)}$=
$\frac{x+2}{-8x-1}$
