Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.7 - Quadratic Equations and Problem Solving - Practice - Page 462: 4

Answer

The two consecutive odd integers are $5$ and $7$ or $-5$ and $-3$.

Work Step by Step

$$x(x+2) = x + (x+2) + 23$$ $$x^2 + 2x = 2x + 25$$ $$x^2=25$$ $$x=±5$$ If $x=5$, then: $$x+2 = 5+2 = 7$$ If $x=-5$, then: $$x+2 = -5+2 = -3$$ Check: $5,7$ $$x(x+2) = x + (x+2) + 23$$ $$5(7) = 5 + 7 + 23$$ $$35=35$$ Check: $-5,-3$ $$-5(-3) = -5 + (-3) + 23$$ $$15=15$$
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