Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.7 - Quadratic Equations and Problem Solving - Practice - Page 461: 3

Answer

Length = 16ft Width = 11ft

Work Step by Step

Recall the formula for the area of a rectangle: $$A=LW$$ Given: L = 5 + W; A=176 Substitute these to the formula: $$A=LW$$ $$176=(5 + W)W$$ $$176=5W + W^2$$ Subtract $176$ from both sides: $$176-176=5W + W^2-176$$ $$5W + W^2-176=0$$ Factor: $$(W+16)(W-11)=0$$ $$W+16=0 \: or \: W-11=0$$ $$W=-16$$ $$W=11$$ Since measurements cannot be negative, therefore the width is equal to $11ft$. Substitute this value to the formula of area: $$A=LW$$ $$176=L(11)$$ Divide both sides by $11$. $$\frac{176}{11}=\frac{L(11)}{11}$$ $$L=16$$ Thus, the length is equal to $16ft$.
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