Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 449: 107

Answer

a) 1,456 ft b) 816 ft c) 10 seconds d) $16*(10-t)(10+t)$

Work Step by Step

a) $t=3$ $h=1600-16t^2$ $h=1600-16*3^2$ $h=1600-16*9$ $h=1600-144$ $h=1456$ b) $t=7$ $h=1600-16t^2$ $h=1600-16*7^2$ $h=1600-16*49$ $h=1600-784$ $h=816$ c) $h=1600-16t^2$ $0=1600-16t^2$ $16t^2=1600$ $16t^2/16=1600/16$ $t^2=100$ $\sqrt {t^2} = \sqrt {100}$ $t=±10$ We can't have a negative time, so $t=10$ d) $1600-16t^2$ $16(100-t^2)$ $16*(10-t)(10+t)$
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