Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 449: 105

Answer

a) 2,560 ft b) 1,920 ft c) 13 seconds d) $16*(13-t)(13+t)$

Work Step by Step

a) $t=3$ $h=2704-16t^2$ $h=2704-16*3^2$ $h=2704-16*9$ $h=2704-144$ $h=2560$ b) $t=7$ $h=2704-16t^2$ $h=2704-16*7^2$ $h=2704-16*49$ $h=2704-784$ $h=1920$ c) $h=2704-16t^2$ $0=2704-16t^2$ $16t^2=2704$ $16t^2/16=2704/16$ $t^2=169$ $\sqrt {t^2} = \sqrt {169}$ $t = ±13$ We can't have a negative time, so $t = 13$ seconds. d) $2704-16t^2$ $16*(169-t^2)$ $16*(13-t)(13+t)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.