Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Exercise Set - Page 436: 69

Answer

$p^{2}(4p-5)^{2}$

Work Step by Step

$16p^{4}-40p^{3}+25p^{2}=p^{2}(16p^{2}-40p+25)$ $16p^{2}-40p+25=(4p-5)(px-5)$ $p^{2}(4p-5)(4p-5)$ $p^{2}(4p-5)^{2}$
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