Answer
$(t^2-3)(2t^2+9)$
Work Step by Step
$2t^4+3t^2-27$
Factors of -27: 1 and -27, 3 and -9, 9 and -3, 27 and -1
Factors of 2: 1 and 2, -1 and -2
$(t^2-3)(2t^2+9)$
$t^2*2t^2+t^2*+9+(-3)*2t^2+(-3)*9$
$2t^4+9t^2-6t^2-27$
$2t^4+3t^2-27$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Exercise Set - Page 436: 75
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