Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Review - Page 476: 95

Answer

The dimension of the rectangle is 6 inches (length) x 2 inches (width).

Work Step by Step

Let $x$ inches be the length of the rectangle Since the width of the rectangle is 4 inches less than its length, the width = $x - 4$ Area = length x width $12 = x \cdot (x - 4)$ $x^2 - 4x - 12 = 0$ $(x - 6)(x + 2) = 0$ $x = 6$ or $x = -2$ (rejected) Therefore, the length = 6 inches and the width = 2 inches. The dimension of the rectangle is 6 inches (length) x 2 inches (width).
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