#### Answer

The solutions are 2 and 3.

#### Work Step by Step

x(x-5)=-6
x(x-5)+6=-6+6
x(x-5)+6=0
$x^{2}$-5x+6=0
$x^{2}$-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-3)(x-2)=0
x-3=0 or x-2=0
x=3 or x=2
The solutions are 2and 3.
Check
Let x=2
x(x-5)=-6
2(2-5)=-6
2(-3)=-6
-6=-6
Let x=3
x(x-5)=0-6
3(3-5)=-6
3(-2)=-6
-6=-6