Answer
$\frac{x}{2y}+\frac{1}{4}-\frac{7}{8y}$
Work Step by Step
$\frac{4x^2+2xy-7x}{8xy}$
$=4x^2(\frac{1}{8xy})+2xy(\frac{1}{8xy})-7x(\frac{1}{8xy})$
$=\frac{x}{2y}+\frac{1}{4}-\frac{7}{8y}$
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