Answer
$A=(4x^{2}-9)$ square inches
Work Step by Step
The top of the table is a rectangle, so its area $(A)$ will be
$A= L \times W,$
where $L=(2x+3)$ inches and $W=(2x-3)$ inches.
Therefore, $A=(2x+3)(2x-3)$
$A=2x(2x-3)+3(2x-3)$
$A=4x^{2}-6x+6x-9$
$A=4x^{2}-9$
Therefore, the area of the table is $A=(4x^{2}-9)$ square inches.