Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Test - Page 408: 9



Work Step by Step

$\frac{6^2x^{-4}y^{-1}}{6^3x^{-3}y^7}$ $=\frac{1}{6}x^{-4-(-3)}y^{-1-7}$ $=\frac{1}{6}x^{-1}y^{-8}$ $=\frac{1}{6xy^8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.