Answer
$\frac{1}{6xy^8}$
Work Step by Step
$\frac{6^2x^{-4}y^{-1}}{6^3x^{-3}y^7}$
$=\frac{1}{6}x^{-4-(-3)}y^{-1-7}$
$=\frac{1}{6}x^{-1}y^{-8}$
$=\frac{1}{6xy^8}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Test - Page 408: 9
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