Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Test: 9

Answer

$\frac{1}{6xy^8}$

Work Step by Step

$\frac{6^2x^{-4}y^{-1}}{6^3x^{-3}y^7}$ $=\frac{1}{6}x^{-4-(-3)}y^{-1-7}$ $=\frac{1}{6}x^{-1}y^{-8}$ $=\frac{1}{6xy^8}$
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