Answer
$\frac{16y^{14}}{x^2}$
Work Step by Step
$(\frac{4x^2y^3}{x^3y^{-4}})^2$
$=\frac{16x^4y^6}{x^6y^{-8}}$
$=16x^{4-6}y^{6-(-8)}$
$=16x^{-2}y^{14}$
$=\frac{16y^{14}}{x^2}$
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