Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice: 6

Answer

$r^{2}-2rs+s^{2}$

Work Step by Step

Step 1: $(r-s)^{2}$ Step 2: Using the special product, $(r-s)^{2}=(r)^{2}-2(r)(s)+(s)^{2}$ Step 3: $(r)^{2}-2(r)(s)+(s)^{2}=r^{2}-2rs+s^{2}$ Step 4: Therefore, the required answer is $r^{2}-2rs+s^{2}$
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