Answer
$r^{2}-2rs+s^{2}$
Work Step by Step
Step 1: $(r-s)^{2}$
Step 2: Using the special product, $(r-s)^{2}=(r)^{2}-2(r)(s)+(s)^{2}$
Step 3: $(r)^{2}-2(r)(s)+(s)^{2}=r^{2}-2rs+s^{2}$
Step 4: Therefore, the required answer is $r^{2}-2rs+s^{2}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.6 - Special Products - Practice - Page 385: 6
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