Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice: 5

Answer

$y^{2}+6y+9$

Work Step by Step

Step 1: $(y+3)^{2}$ Step 2: Using the special product, $(y+3)^{2}=(y)^{2}+2(y)(3)+(3)^{2}.$ Step 3: $(y)^{2}+2(y)(3)+(3)^{2}=y^{2}+6y+9.$ Step 4: Therefore, the required answer is $y^{2}+6y+9.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.