## Algebra: A Combined Approach (4th Edition)

$(6x^{2}-4x)$ inches$^{2}$
We know that the area of a triangle is calculated as $\frac{1}{2}\times base \times height$. We are given that the base is $(3x-2)$ inches and the height is $4x$ inches. Therefore, $Area=\frac{1}{2}\times(3x-2)\times 4x=\frac{4x}{2}\times(3x-2)=2x(3x-2)=(2x)(3x)+(2x)(-2)=(6x^{2}-4x)$ inches$^{2}$.