## Algebra: A Combined Approach (4th Edition)

$(4x^{2}-25)$ yards$^{2}$
We know that the area of a rectangle is calculated as $length\times width$. We are given that the length of the rectangle is $(2x-5)$ yards and the width of the rectangle is $(2x+5)$ yards. Therefore, $Area=(2x-5)(2x+5)=2x(2x+5)-5(2x+5)=(2x)(2x)+(2x)(5)-5(2x)-5(5)=4x^{2}+10x-10x-25=(4x^{2}-25)$ yards$^{2}$.