Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set - Page 379: 49

Answer

$10a^{3}-27a^{2}+26a-12$

Work Step by Step

$(2a-3)(5a^{2}-6a+4)=2a(5a^{2}-6a+4)-3(c-6a+4)=(2a)(5a^{2})+(2a)(-6a)+(2a)(4)-3(5a^{2}-6a+4)-3(-6a)-3(4)=10a^{3}-12a^{2}+8a-15a^{2}+18a-12=10a^{3}-27a^{2}+26a-12$
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