Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set: 39

Answer

$12x^{2}-29x+15$

Work Step by Step

$(4x-3)(3x-5)=4x(3x-5)-3(3x-5)=(4x)(3x)+(4x)(-5)-3(3x)-3(-5)=12x^{1+1}-20x-9x+15=12x^{2}-20x-9x+15=12x^{2}-29x+15$
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