Answer
$\dfrac{5}{16}x^{3}-14x^{2}-\dfrac{3}{16}x+\dfrac{1}{8}$
Work Step by Step
$\dfrac{5}{16}x^{3}-\dfrac{1}{8}+\dfrac{3}{8}x+\dfrac{1}{4}-\dfrac{9}{16}x-14x^{2}$
Simplify the expression by combining like terms:
$\dfrac{5}{16}x^{3}-14x^{2}+\Big(\dfrac{3}{8}-\dfrac{9}{16}\Big)x+\Big(\dfrac{1}{4}-\dfrac{1}{8}\Big)=...$
$...=\dfrac{5}{16}x^{3}-14x^{2}+\Big(\dfrac{48-72}{128}\Big)x+\dfrac{8-4}{32}=...$
$...=\dfrac{5}{16}x^{3}-14x^{2}-\dfrac{24}{128}x+\dfrac{4}{32}=...$
$...=\dfrac{5}{16}x^{3}-14x^{2}-\dfrac{3}{16}x+\dfrac{1}{8}$
