Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.3 - Introduction to Polynomials - Exercise Set: 41

Answer

$\dfrac{3}{20}x^{3}+6x^{2}-\dfrac{13}{20}x-\dfrac{1}{10}$

Work Step by Step

$\dfrac{3}{20}x^{3}+\dfrac{1}{10}-\dfrac{3}{10}x-\dfrac{1}{5}-\dfrac{7}{20}x+6x^{2}$ Simplify the expression by combining like terms: $\dfrac{3}{20}x^{3}+6x^{2}-\Big(\dfrac{3}{10}+\dfrac{7}{20}\Big)x+\Big(\dfrac{1}{10}-\dfrac{1}{5}\Big)=...$ $...=\dfrac{3}{20}x^{3}+6x^{2}-\Big(\dfrac{60+70}{200}\Big)x+\Big(\dfrac{5-10}{50}\Big)=...$ $...=\dfrac{3}{20}x^{3}+6x^{2}-\dfrac{130}{200}x-\dfrac{5}{50}=...$ $...=\dfrac{3}{20}x^{3}+6x^{2}-\dfrac{13}{20}x-\dfrac{1}{10}$
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