Answer
$-\frac{4x^{2}}{y^{4}}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $-\frac{32x^{-3}y^{-6}}{8x^{-5}y^{-2}}=-\frac{32}{8}\times x^{-3-(-5)}\times y^{-6-(-2)}=-4\times x^{2}\times y^{-4}=-4\times x^{2}\times\frac{1}{y^{4}}=-\frac{4x^{2}}{y^{4}}$.
