Answer
$\frac{x^{6}}{3y^{5}z^{3}}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{5x^{7}y^{3}z^{0}}{15xy^{8}z^{3}}=\frac{5}{15}\times x^{7-1}\times y^{3-8}\times z^{0-3}=\frac{1}{3}\times x^{6}\times y^{-5}\times z^{-3}=\frac{1}{3}\times x^{6}\times\frac{1}{y^{5}}\times \frac{1}{z^{3}}=\frac{x^{6}}{3y^{5}z^{3}}$.
