Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Practice: 14

Answer

$\frac{x^{6}}{3y^{5}z^{3}}$

Work Step by Step

We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer). Therefore, $\frac{5x^{7}y^{3}z^{0}}{15xy^{8}z^{3}}=\frac{5}{15}\times x^{7-1}\times y^{3-8}\times z^{0-3}=\frac{1}{3}\times x^{6}\times y^{-5}\times z^{-3}=\frac{1}{3}\times x^{6}\times\frac{1}{y^{5}}\times \frac{1}{z^{3}}=\frac{x^{6}}{3y^{5}z^{3}}$.
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