Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review - Page 406: 95



Work Step by Step

$(x+7)(x^3+4x-5)=x(x^3+4x-5)+7(x^3+4x-5)$ $x^4+4x^2-5x+7x^3+28x-35=x^4+7x^3+4x^2+23x-35$
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