Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review - Page 406: 113

Answer

$\frac{1}{7}+\frac{3}{x}+\frac{7}{x^2}$

Work Step by Step

$\frac{x^2+21x+49}{7x^2}$ $=x^2(\frac{1}{7x^2})+21x(\frac{1}{7x^2})+49(\frac{1}{7x^2})$ $=\frac{1}{7}+\frac{3}{x}+\frac{7}{x^2}$
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