Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.4 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 318: 1


c. length = 9 feet; width = 6 feet

Work Step by Step

Let $l$ be the length of the rectangle. Let $w$ be the width of the rectangle. Length is 3 feet longer than the width. $l=w+3$ Perimeter is 30 feet. $2l+2w=30$ $l=w+3$ $2l+2w=30$ $2(w+3)+2w=30$ $2w+6+2w=30$ $4w+6=30$ $4w=24$ $w=6$ $l=w+3$ $l=(6)+3$ $l=9$ Length is 9 feet and width is 6 feet, so the answer is c.
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