## Algebra: A Combined Approach (4th Edition)

Write the first equation as a solution for x in terms of y: 7x - 3y = 2 7x = 3y + 2 x = $\frac{3}{7}y + \frac{2}{7}$ Substitute x in the second equation with the equation in terms of y and solve for y: 6($\frac{3}{7}y + \frac{2}{7}$) + 5y = -21 $\frac{18}{7}y + \frac{12}{7}$ + 5y = -21 $\frac{53}{7}y = -\frac{159}{7}$ y = -3 Let y = -3 in the first equation to solve for x: x = ($\frac{3}{7})(-3) + \frac{2}{7}$ x = -1 Check the solution (-1, -3) in the second equation: 6(-1) + 5(-3) = -21 -6 - 15 = -21 -21 = -21; True