## Algebra: A Combined Approach (4th Edition)

($\frac{1}{3}$, 1)
Write the first equation as a solution for x: x = $\frac{1}{2} - \frac{1}{6}y$ Insert the equation for x in terms of y in the second equation: 3($\frac{1}{2} - \frac{1}{6}y$) + 2y = 3 $\frac{3}{2} - \frac{1}{2}y$ + 2y = 3 $\frac{3}{2} + \frac{3}{2}y$ = 3 $\frac{3}{2}y = \frac{3}{2}$ y = 1 Let y = 1 in the first equation to solve for y: x + ($\frac{1}{6})1 = \frac{1}{2}$ x = $\frac{1}{3}$ Check the solution ($\frac{1}{3}$, 1) in the second equation: 3($\frac{1}{3}$) + 2(1) = 3 1 + 2 = 3 3 = 3; True