# Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set - Page 300: 5

x=2 y=7

#### Work Step by Step

y = 3x +1 4y - 8x = 12 Substitute y = 3x + 1 to the second equation. 4 ( 3x + 1 ) - 8x = 12 12x + 4 - 8x = 12 ( use the distributive property ) 4x +4 =12 ( simplify) 4x +4 - 4 = 12 - 4 4x =8 (divide both sides by 4 ) x=2 Substitude x = 2 to the first equation. y= 3 $\times2$ + 1 y=6+1 y=7

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