Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Exercise Set: 17

Answer

No solution

Work Step by Step

1. Solve the second equation for x: -2x = y + 4 x = $\frac{y + 4}{-2}$ 2. Substitute x into the first equation: 4($\frac{y + 4}{-2}$) + 2y = 5 3. Solve for y. -2(y + 4) + 2y = 5 -2y - 8 + 2y = 5 -8 = 5 This equation is false, so there is no solution to the system of equations.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.