## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set: 8

a. no b.no

#### Work Step by Step

To find out if an ordered pair is a solution you need to insert the values of the variables into the equation. If the answer of the system is true, the pair is a solution, if not it isn't. a. $4\times0=1-1<=>0=0$ $0-3\times1=-8<=>-3\ne-8$ b.$4\times\frac{1}{6}=1-\frac{1}{3}<=>\frac{2}{3}=\frac{2}{3}$ $\frac{1}{6}-3\times\frac{1}{3}=-8<=>-\frac{5}{6}\ne-8$

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