Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set - Page 289: 7

Answer

a.no b. no

Work Step by Step

To find out if an ordered pair is a solution you need to insert the values of the variables into the equation. If the answer of the system is true, the pair is a solution, if not it isn't. a. $-2=-2-6\times0<=>-2=-2$ $6\times-2-0=13<=>-12\ne13$ b.$-2=\frac{1}{2}-7\times\frac{5}{14}<=>-2=-2$ $6\times\frac{1}{2}-\frac{5}{14}=13<=>\frac{37}{14} \ne13$
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