Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Review - Page 328: 27

Answer

$$x=8$$ $$y=-6$$

Work Step by Step

equation 1 $$\frac{3}{4}x+\frac{2}{3}y=2$$ equation 2 $$x+\frac{y}{3}=6$$ Multiply equation 2 by $-2$: $$[x+\frac{y}{3}=6]\cdot-2$$ $$-2x-\frac{2}{3}y=-12$$ Add this to equation 1: $$\frac{3}{4}x+\frac{2}{3}y=2$$ $$-2x-\frac{2}{3}y=-12$$ $$-\frac{5}{4}x=-10$$ $$-5x=-40$$ $$x=8$$ Substitute this value of $x$ to equation 2: $$x+\frac{y}{3}=6$$ $$8+\frac{y}{3}=6$$ $$\frac{y}{3}=6-8$$ $$\frac{y}{3}=-2$$ $$y=-6$$
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