Answer
True for all values of $x$ and $y$.
Work Step by Step
equation 1 $$2x - 6y = -1$$ equation 2 $$-x + 3y =\frac{1}{2}$$
Multiply equation 2 by $2$:
$$[-x + 3y =\frac{1}{2}]\cdot 2$$ $$-2x + 6y =1$$
Subtract this equation to equation 1:
$$2x - 6y = -1$$ $$-2x + 6y =1$$ $$0=0$$
Then the system is true for all values of $x$ and $y$.
