#### Answer

$x\gt\frac{14}{3}$

#### Work Step by Step

$-6x+2\lt-3(x+4)$
$-6x+2\lt-3x-12$
$-3x\lt-14$
$x\gt\frac{14}{3}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$x\gt\frac{14}{3}$

$-6x+2\lt-3(x+4)$
$-6x+2\lt-3x-12$
$-3x\lt-14$
$x\gt\frac{14}{3}$

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